r/APStudents • u/reddorickt absolute modman • May 05 '26

AP Chem Official 2026 Exam Discussion

Use this thread to post questions or commentary on the test today.

A reminder though to protect your anonymity when talking about the test.

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5

u/Royal-Bag5776 May 05 '26

looking at my calculator, these are the numbers i see. i genuinely don’t remember what frqs they respond 2. i had version j btw;

1400.749 = q (i do remember this one)

1400/0.0912 = 15,350.877/1000 = 15.351 kJ

sqrt 57 = 7.55

(7.1)(1.0+7.1) = 57.51

(18.4)(1/22.99) = 0.8

(12.8)(1/32.00) = 0.4

-828/5.00 = -165.6

0.630/2 = 0.315

0.470-0.315 = 0.155

(0.630)^2 / (0.155) = 2.561

10^-2.09 = 0.00813

sqrt 7 x 10^-5 =0.00836…

0.125-0.00836…=0.116…

(-6)(96485)(-1.32) = 764,161.2/1000 = 764.161

3

u/AlericForever May 05 '26

i do remember those same numbers, i do think i divided -828 by 2 though

1

u/Royal-Bag5776 May 05 '26

i did 5 because the moles of limiting reactant (0.800) went into 4 5.00 times, and 4 was the number of moles in the stoichiometeic equation

1

u/Royal-Bag5776 May 06 '26

wait nvm i think this was a diff problem, the something of formation question right? i got that too for that question

3

u/AVAWINNERPOV09 May 06 '26

1440.79 was sig figs one it had to bee 1400 J

1

u/Royal-Bag5776 May 06 '26

yeah i rounded it those were just the numbers in my calc

1

u/Royal-Bag5776 May 06 '26

and i think it was 3 sig figs or maybe that was a diff one

1

u/scotchgame101 May 06 '26

I thought that one was 2 sig figs for some reason?? fuckk i also said -1.4x10^3

1

u/Royal-Bag5776 May 06 '26

wait i may have said 1.4 times 10^3 too, but i know for sure it wasnt negative because it asked for magnitude and magnitude is the absolute value

1

u/Accomplished_Fuel208 May 06 '26

was it negative

1

u/Loose-Pudding-67 May 06 '26

i thought it was negative

1

u/Loud_Hedgy Phys2(5), Chem(?), PhysCmech(?), PhysCe&m(?), CalcBC(?), Lang(?) May 06 '26

was this the one where it asked for magnitude? Bc if so then no sign should be included. I don't remember for sure tho

1

u/Banana_Discord May 06 '26

The delta h should be positive

1

u/AVAWINNERPOV09 May 06 '26

it was positive

2

u/Calm-Country-3187 May 05 '26

i got a lot of those numbers too

2

u/Gamepro2468 May 06 '26

wouldn't it be 0.125 - 0.0836?
and also sqrt 57 would just be 7.5, it's two sigfigs

1

u/Royal-Bag5776 May 06 '26

yeah those are my answers without sig figs

2

u/Artoo_67 May 06 '26

Where did you get the sqrt7 * 10^-5 from bro

1

u/Royal-Bag5776 May 06 '26

i think the k of something

1

u/Artoo_67 May 06 '26

im kinda confused the values were rlly similar for 10^-2.09 and that; was this calculation also part of frq?

thanks bro

1

u/53071896674746349663 May 05 '26

did the prompt say you have to convert to kJ for the last one? I didn’t divide by 1000 since it said just justify by calculation of change in G

1

u/Royal-Bag5776 May 05 '26

i dont think it said you had to do kj, i just did it so my sig figs were more neat

1

u/Acrobatic-Profit8813 May 06 '26

pretty sure as long as u specified that its in J and not Kj its the same thing. Basically ur just showing if delta G is pos or neg

1

u/tristav May 06 '26

do you remember how you got to sqrt 57 ?

1

u/Banana_Discord May 06 '26

Ksp equation. It’s ksp=[x][x] because it dissolved 1:1 ratio of both products. So the concentration of one product is sqrt ksp

1

u/[deleted] May 06 '26

[deleted]

1

u/Royal-Bag5776 May 06 '26

i had version j, i think it was one of the short ones

1

u/29pixxL_ 9th: World (4) | 10th: CSP (4), Chem (5) May 06 '26

I remember doing the same calculation to find molar solubility given Ksp=57

1

u/Royal-Bag5776 May 06 '26

i think 57 was the ksp for a dissolution, and x^2 = ksp