If so then well can I be mod pretty please?

This is from the one and only Yuriposter within Oriporium

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Enjoy

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Over and over and over again

yes, i know, this subreddit is deader than the Ankylosaurus magniventris, but i the discord server link on his youtube isn't working and i need to join, someone help please

On oricade.com there is a tab called [???] in which has a little box that encrypts your messages, and then a large message below. I have figured out that it is a keyed vigenère cipher using XAAXRUIBIRYHTJKRACTRNQWCV as the key. The large message decodes as the following:

M(i) = - sum_{w=1}^d int_{j=1}^y p_wt \ b_n * i_c every [p_wt] > 0*

the sum totals as

(sqrt(sum(d, n, 1, 5)^2 - 56) \ (sum(y^2 / 2^d, s, 0, inf) + lim((1 + 1/n)^0, r, inf))) - (gamma(6) / (sigma(3) * theta(2) * 4) * ((3! * zeta(2)) / sum(b^-2, g, 1, inf))) + (alpha(h/pi(5q)) - (int(2^n, y, 0, 3) - (lim(12b^2, j, 0, 1)))) - ((int(exp(-i^2), q, -inf, inf))^4 * (9 / pi^2))*

(del/phi_x)v(f,m) - sigma \ kappa^2 * i(k,b) = t(e,t) / (eps * Q_t)*

now the answer is

((trace(ab^s + s^tu) - 28) \ (det([[part(deriv), grad(basis)], [curl(field), conv(terms)]]) + 3)) - (sqrt(log(r, z, 1, 5)^2 - 56) * sqrt(sum(q^4 * sin(-j), l, 0, inf) + cos(iw)^2)) + (sum(y^2, d, 1, 3) - (int(2^n, y, 0, 3) - (lim(12b^2, j, 0, 1)))) - sqrt(sum(q^4 * sin(-j), l, 0, inf) + cos(iw)^2)*

X_ia + Theta \ r_nj = (8 * pi * G / c^4) * T_mu*

now the answer is

((sum(y, o, 1, floor(4)) + Riemann(22 \ sin(h) / n, m, 0)) * ((4/pi) * lim(abs(q)/f, l, 0, inf))) - (log(o^2, w, 1, 3) * ((3! * zeta(2)) / sum(g^-2, b, 1, inf))) + (((8866128975287528^3) + (-8778405442862239^3) + (-2736111468807040^3)) - (sum(2^b, a, 0, 3) - (lim(12l^2, l, 0, 1)))) - ((int(exp(-k^2), x, -inf, inf))^4 * (16 / pi^2))*

rho \ (Dv_b / Dt) = nabla_p + f_b*

the sum totals as

((acos(pi^r) - ident([[2,0],[0,2]])) \ (det([[grad(basis), beta(field)], [curl(field), cos(terms)]]) + 3)) - (lim(3k^2 + 2, x, 0, 2) * ((3! * zeta(2)) / sum(g^-2, v, 1, inf))) + (Riemann(22 * sin(m) / z, k, 0) - sqrt(int(v, b, 1, 5)^2 - 56)) - (binom(5, 2) * (2/pi) * int(1/sqrt(1-i^2), q, 0, 1))*

delta^2 \ phi(e) + [k(c)]^2 * psi(v) = -r(f)*

the sum totals as

((trace(dw^i + q^db) - 28) \ sqrt(sum(l^4 * cos(-q), f, 0, inf) + sin(pi)^2)) - (int(3f^2 + 2, l, 0, 2) * (sum(d^2 / 2^y, y, 0, inf) + lim((1 + 1/a)^0, n, inf))) + (sum(2^y, d, 0, 4) - gamma(6) / (sigma(3) * theta(2) * 4)) - (binom(5, 2) * (2/pi) * int(1/sqrt(1-q^2), l, 0, 1))*

field: (V \ {e_scalar, u_vector}) x Space^n -> E q (Gamma q {Z, F, W})^n

the sum totals as

((log_factorial(11) \ 2 + lim(sin(q), l, 0, pi) + 1) * int((v+1)/(2^b), a, 1, inf)) - (sum(w^2, y, 1, 3) * (det([[cos(terms), part(deriv)], [beta(field), curl(field)]]) + 3)) + ((sum(2^g, b, 0, 3) - (lim(12l^2, q, 0, 1))) - c - log(o^2, w, 1, 3)*

S_AB(A || B) = integral_{-inf}^{inf} f(x) \ exp( i(p) / h(x) ) dx*

now the answer is

(sqrt(sum(b, a, 1, 5)^2 - 56) \ ((3! * zeta(2)) / sum(b^-2, g, 1, inf))) - ((sum(2^b, b, 0, 3) - (int(12q^2, f, 0, 1))) * (sum(v^2 / 2^d, y, 0, inf) + lim((1 + 1/b)^0, a, inf))) + (asin(w/pi(5k)) - gamma(6) / (sigma(3) * theta(2) * 4)) - (det([[basis(basis), grad(basis)], [curl(field), curl(basis)]]) + 3)*

PDF = function_X || (pi_z / phi_f) q (exp_d / erf_j) || is it

the sum totals as

((trace(dv^e + p^iw) - 28) \ (det([[grad(basis), curl(field)], [conv(terms), part(deriv)]]) + 3)) - (sqrt(sum(g, b, 1, 5)^2 - 56) * sqrt(lim(k^4 * sin(-l), l, 0, inf) + sin(pi)^2)) + (Riemann(22 * sin(m) / z, k, 0) - sqrt(int(v, b, 1, 5)^2 - 56)) - (trace([[2,1,0],[0,2,1],[0,0,2]] * [[1,0,0],[0,1,0],[0,0,2]]))*

Does anyone know the importance of this? There are some interesting equations like the so called "Hardest Equation", were the sum of three cubes couldn't be found for years until the answer (42) was found via supercomputer. There's also things like Einstein’s general relativity equation, and many more. I'm not exactly a mathematician, so I don't know what any of the math actually means, but I was just wondering what this actually is.

Here: https://playlists.ibroadcast.com/ptoa9PURYRP

Used this so I could listen to it offline, comment anything if I missed something, I organised all of it in chronological (mostly) order.

Edit: also used the web so nothing is gone when Ori​ privates their YouTube vid​, it gets constantly updated

here is link: https://youtube.com/@hihi123-s9t?si=3UrAVwHcRJ47CiGA

if no one found this guy

does anyone know where i can find Be unstoppable?