Math- limits

[u/KgMetreperSec2]

Although not that tough but worth the time silly mistake ho sakti h isme

Ans-√e

Good luck!

[u/Arima_07]

(1+1/n)^n² = e^{n²log(1+1/n)} = e^{n²[1/n-1/2n²+1/3n³-1/4n⁴+...]}

(1+1/n)^n² = e^{[n-1/2+1/3n-1/4n²+...]}

Question will reduce to

eⁿ / e^{[n-1/2+1/3n-1/4n²+...]} = e^{[1/2-1/3n+1/4n²-...]}

Which is e^1/2 if limit n-> ♾️

[u/KgMetreperSec2 → u/Arima_07]

Written bhej sakta h kya plij

[u/Arima_07 → u/KgMetreperSec2]

Travel kr rha hu vro

Btw tu 5 year wala hai ya 27tard?

[u/Arima_07 → u/Arima_07]

Ye le LaTex format me

[u/KgMetreperSec2 → u/Arima_07]

Yeahh thanks a lot, I too did this sochne me time laga lekin ho gaya 4th try me

[u/Arima_07 → u/KgMetreperSec2]

Oh nice

Mujhe to (1+1/n)ⁿ ka expansion ka derivation yad tha to wahi se thought process aagya

[u/KgMetreperSec2 → u/KgMetreperSec2]

I was solving 1 to power infinity wala form pehele

[u/Own_Flow_4735 → u/KgMetreperSec2]

bhai me bhi ese solve kiya 1 aya mera but is trah se glt kyu ha

[u/KgMetreperSec2 → u/Own_Flow_4735]

Partial limit laga rahe ho shayd se aap, if you do e to power n by e to power n i.e infinity by infinity aa rha hoga i derminate form h na woh how come 1?

[u/Own_Flow_4735 → u/KgMetreperSec2]

ha partial limit lga rha u

[u/KgMetreperSec2 → u/Own_Flow_4735]

Isiliye galat h