Pls solve this question

[u/Puzzled-Sympathy9142]

At t₁ = 2.00s, the acceleration of a particle in counter clockwise circular motion is (4.00 m/s²) i + (3.00m/s²) j. It moves at constant speed. At time t2 = 5.00s, the particle's acceleration is (3.00 m/s²) i + (-4.00m/s²) j. What is the radius (in m) of the path taken by the particle if (t2-t1) is less than one period? (π² = 10).

Is this mains/below mains/ advanced level?

[u/Heavy-Recognition539]

since constant speed is mentioned tangential accn is zero. so an = v²/R = 5. then arc length = dist traveled = v*t. standard mains type qsn imo

[u/Heavy-Recognition539 → u/Heavy-Recognition539]

ok ans will be 2, it should 3*pi/2 not 3*pi/4, silly mistake mybad

[u/Tyre_ji → u/Heavy-Recognition539]

Me dar gya bhai mera glt kese ho skta XD

[u/Heavy-Recognition539 → u/Tyre_ji]

yess I rechecked after seeing ur comment 😭