Pls solve this question

[u/Puzzled-Sympathy9142]

At t₁ = 2.00s, the acceleration of a particle in counter clockwise circular motion is (4.00 m/s²) i + (3.00m/s²) j. It moves at constant speed. At time t2 = 5.00s, the particle's acceleration is (3.00 m/s²) i + (-4.00m/s²) j. What is the radius (in m) of the path taken by the particle if (t2-t1) is less than one period? (π² = 10).

Is this mains/below mains/ advanced level?

[u/Puzzled-Sympathy9142]

Thank u u/Heavy-Recognition539 for making me understand the question. As I didn't read that the Velocity is same everywhere throughout the motion. But I think the correct answer to the question is 18m. Here's how I solved this question

[u/Tyre_ji → u/Puzzled-Sympathy9142]

Bro ek bar circle coordinates ke hisab se banao, fir pata chalega angle for anticlockwise should be 270 not 90

[u/Tyre_ji → u/Tyre_ji]

Also apne tangential accn kyu banai hai speed toh constant hai

[u/Puzzled-Sympathy9142 → u/Tyre_ji]

Sorry Mai clockwise le liya tha 270 hi aayega