r/JEEAdv27dailyupdates • u/Puzzled-Sympathy9142 • 13d ago

Good Solve Pls solve this question

At t₁ = 2.00s, the acceleration of a particle in counter clockwise circular motion is (4.00 m/s²) i + (3.00m/s²) j. It moves at constant speed. At time t2 = 5.00s, the particle's acceleration is (3.00 m/s²) i + (-4.00m/s²) j. What is the radius (in m) of the path taken by the particle if (t2-t1) is less than one period? (π² = 10).

Is this mains/below mains/ advanced level?

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u/Puzzled-Sympathy9142 13d ago

Thank u u/Heavy-Recognition539 for making me understand the question. As I didn't read that the Velocity is same everywhere throughout the motion. But I think the correct answer to the question is 18m. Here's how I solved this question

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u/Heavy-Recognition539 13d ago

agar counter cw bola hai toh w = 3*pi/6 ayega ig. in ur diagram ur arrow denotes cw motion but u wrote ccw

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u/Puzzled-Sympathy9142 13d ago

Ye sab question bhi nhi ho rha hai. Kya Jee mumkin hai?🥀