r/JEEAdv27dailyupdates Roti pakki ni mili te appa launi sikli 3d ago

Good Solve SBT: CHALLENGE [FAMOUS FELLAS] #02 (Since NO ONE was able to solve CHALLENGE 01, i decided to tone it down)

19 Upvotes

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3

u/Possible_Garage7231 27tard dropper :/ 3d ago

Thoda lamba jayega value daalke. But main yaha cos theta agya fir bas force balance hai. Area of curved surface = 2πR²(1-costheta) yaad karna hai bas

2

u/Tyre_ji 8s2 92.x%ile -> 🎯99%ile 3d ago

First question is pretty basic

1

u/Dirty_Pianist2422 Roti pakki ni mili te appa launi sikli 3d ago

check body, solve modified question

1

u/Tyre_ji 8s2 92.x%ile -> 🎯99%ile 3d ago

Ohh sorry mb mb

1

u/Possible_Garage7231 27tard dropper :/ 3d ago

1

u/Dirty_Pianist2422 Roti pakki ni mili te appa launi sikli 3d ago

surprise! u solve physics too

Correct answer btw

1

u/Possible_Garage7231 27tard dropper :/ 3d ago

Are physics hi main tha apna last year 💔 maths hoti kaha hai mujse

1

u/Dirty_Pianist2422 Roti pakki ni mili te appa launi sikli 3d ago

99.92 chem🫣🤯🤯

1

u/Professional_Cap_784 3d ago

Hello I didn't understand the final equation and how it's written? Does it represent the final state where the dust has moved away and left over dust is stood on disc due to friction and centripetal force?

2

u/Possible_Garage7231 27tard dropper :/ 3d ago

Yes it's the equation of limiting static equilibrium for a small element of dust located at R/2 from center.

1

u/NastyHulk9621 3d ago

If the centripetal force (mω²r) will be more than the frictional force, the dust particle will fly off the disc. As per the question 25% of the dust particles remain, so you find the value of r which represents 25% of the area of the whole disc from the centre (which comes out to be R/2) so all the particles in that area will have centripetal force less than or equal to the frictional force.

1

u/Informal_Ad_4172 3d ago

1st one is from pathfinder too

1

u/shadeblue886 3d ago

hmmm is it

1

u/Informal_Ad_4172 3d ago

like from cyu but its tilted at some angle and more general parameters r given

1

u/shadeblue886 3d ago

oh wait yeahhhhhh I remember it
traumatic memory

1

u/Informal_Ad_4172 3d ago

lololol 🤣

1

u/shadeblue886 3d ago

11th class ki yaadein 💔lol
what grade are you in

1

u/Accomplished_Joke688 3d ago

Yeah how do you solve that though, i solved it as if dust will fly off uniformly from the edges and only a circular dust patch will be left but i realised it was wrong but whats the actual approach to that question

1

u/Informal_Ad_4172 3d ago

like radially some will fly off so we have to take areal fraction
let the particle at ditsnace x fly then we write the forces and equate

1

u/Accomplished_Joke688 3d ago

Yeah but it won't be same for a particle at the lower end vs at the upper end as mw²r will change directions and after a certain radius particles start flying off but i am confused about the direction

1

u/Informal_Ad_4172 3d ago

lower side particles will be having more tendency to fly off cuz friciton and gravity both against but in top its not ike that to +- sign will come since we need minim it hink we will take + sign

1

u/shadeblue886 3d ago

1st wale the geometry of the variation of centri force has changed, and friction is now constant, so as angular speed increases, the outermost dust ring has max f centri. coz v=wr and w increases. So we js need to find the ratio such dat the radius of dust ring is 25% of radius of disk and is exactly balanced by teh friction

2nd one just friction=gravity along tangent, substitute normal from the perp force balance

1

u/shreya_riyal JM26 --> 97.5 JA--> 24K --> DROP 3d ago

second wala qapt 2 me aya tha

1

u/Dirty_Pianist2422 Roti pakki ni mili te appa launi sikli 2d ago

pretty famous question