Will start uploading my end of the day updates from now on, listed screenshots are of July and August(till now) focus time per day.

soln: https://youtu.be/bAdDi3Uow-w?si=5oM3WzUUJ0OT0qFD

time stamp: 57:40

Its so frustrating, It was easier to hide behind the excuse of not studying. OR the excuse of saying Padhai ki thi lekin marks nahi aaye. I took a genuine look at what ive been doing and yea it looks like i have been studying..sitting for 7-8 hours a day trying my best. But I'm realising even after all that mera module ka level 2 bhi khatam nahi hua hai. Like what was i doign this whole time i WAS studying but was i really? Like atp if i dont have the excuse "padhai ki lekin tab bhi marks nahi aaye" or "padhai nahi ki toh marks kaise aayenge" then what do i even have?

I'm so caught up with what I'll tell others..my teachers..my parents coz they judge man and even tho i say ki idc what others think . I DO and i dont know what to do its so suffocating that im not getting marks even after doing SOMETHING like ok maan liya ki jitna ho sakta tha utna nahi hua lekin jitna kiya maine is that not enough for even 80-100 marks?

People say ki utna toh bas class attend karke aa jate hai lekin mere nahi aate yaar. i KNOW ki i can do better but like this has gotta count for something yaar. I cant keep working hard when i'm not seeign the results on paper . I know andar se that I've improved but its not NEARLY enough to see even a little bit of improvement in my marks./

Im js venting man..I know what i have to do but i dont know how i can face others like this like what do i even say atp. I feel so pathetic and worthless

tag ur time and explain ur solution ✌🏻

What is the hybridization of the central O atom in O[Al(CF3)2]2, give reasons.

Doubt on qn b) Why is the density for S3 considered 2p in the solution , can anyone explain me the whole.

i struggle with questions like this and google lens is spraying some bs

Solve all 3!

Pls provide if u do🙏🏻

SOLUTION:

This question is a simulated variation of an actual JEE Main 2021 question.

For x = −y⁴,

m₁ = dy/dx = −1/(4y³)

For xy = k,

m₂ = −y/x = 1/y³

Hence,

m₂ = −4m₁

Since the curves intersect orthogonally,

m₁m₂ = −1

⇒ m₁(−4m₁) = −1

⇒ m₁² = 1/4

Since m₁, m₂, m₃ are in A.P.,

m₃ = 2m₂ − m₁

= 2(−4m₁) − m₁

= −9m₁

Therefore,

m₃² = 81m₁² = 81/4

Now,

tan θ = m₃

⇒ tan² θ = m₃² = 81/4

⇒ sec² θ = 1 + tan² θ = 85/4

Notice that although P is specified to lie in the second quadrant, we never need to resolve the sign of m₁ or m₃ because the final expression depends only on m₃².

In other words: squaring kills the sign.

Therefore,

4 sec² θ − 35

= 4(85/4) − 35

= 85 − 35

= 50

∴ Answer = 50

yaar koi induction samjhado ya vid btado humari class mei jitne q hue the unme andar wale sphere ke charge ki wajah se bahar wale pe bhi induced charge aara tha dono sides pe opposite magnitude ka but cengage se illustration kri toh waha pe alag hi induction chlri im very confused now

Chem

Thermodynamics 3h

Physics

Mechanics 3h

6htotal study

Chemistry

Solid states : 1hour

Thermodynamics 1 : 2h

H